7+2[1+2(2x-2)]=6(x+7)

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Solution for 7+2[1+2(2x-2)]=6(x+7) equation:


Simplifying
7 + 2[1 + 2(2x + -2)] = 6(x + 7)

Reorder the terms:
7 + 2[1 + 2(-2 + 2x)] = 6(x + 7)
7 + 2[1 + (-2 * 2 + 2x * 2)] = 6(x + 7)
7 + 2[1 + (-4 + 4x)] = 6(x + 7)

Combine like terms: 1 + -4 = -3
7 + 2[-3 + 4x] = 6(x + 7)
7 + [-3 * 2 + 4x * 2] = 6(x + 7)
7 + [-6 + 8x] = 6(x + 7)

Combine like terms: 7 + -6 = 1
1 + 8x = 6(x + 7)

Reorder the terms:
1 + 8x = 6(7 + x)
1 + 8x = (7 * 6 + x * 6)
1 + 8x = (42 + 6x)

Solving
1 + 8x = 42 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
1 + 8x + -6x = 42 + 6x + -6x

Combine like terms: 8x + -6x = 2x
1 + 2x = 42 + 6x + -6x

Combine like terms: 6x + -6x = 0
1 + 2x = 42 + 0
1 + 2x = 42

Add '-1' to each side of the equation.
1 + -1 + 2x = 42 + -1

Combine like terms: 1 + -1 = 0
0 + 2x = 42 + -1
2x = 42 + -1

Combine like terms: 42 + -1 = 41
2x = 41

Divide each side by '2'.
x = 20.5

Simplifying
x = 20.5

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